Question

The refractive index of water is formed to have the values 1.29,1.33,1.34,1.33,1.30,1.35,1.36,1.32Calculate a) the mean valueb) absolute errorc) relative error d) percentage error

Answer 1

Heya!!!

Here's the answer to your question

a) Mean value = sum of all the observations / total number of observations

Here mean value = Sum / 8 = 10.62/8= 1.32

b) Absolute for each observation is as follows
0.03, 0.01, 0.02, 0.01, 0.02, 0.03, 0.04, 0

c) Relative error = sum of absolute errors / number of observations

Here Relative error = 0.16 / 8 = 0.02

d) Percentage error
= (Relative error × 100) / mean
=(0.02×100) / 1.32 = 2/1.32 = 1.5%

HOPE THIS HELPS.... :-)