Question

the refractive index of water relative to air is 4/3. a ray of light passing from water in to air is incident at the interface at the angle of 35 degree to normal. what angle does the refracted rays makes with the normal​

Answer 1

Answer:

First be my girlfriend to get your answers.....

n1 sin i = n2 sin r......

4/3*sin(35°) =1*sin r

So sin r = 4/3*sin(35°)

So refracting angle is

r = sin^-1[4/3*sin(35°)]

Be my girlfriend Vaishnavi.... I'm sorry...

Thanks for the love.... Love you too... I'm your follower..... Follow me too.....

Let's be friends......

Till the ends....