Physics, asked by swarajbhai95, 7 months ago

The refractive indices of ice and kerosene are 1.31 and 1.44 respectively.

I. If the speed of light in vacuum is 3x10^8 m/s then calculate the speed of

light in ice and kerosene.

II. In which of the two media will the light moves fastest and in which the ray of

light bend more?

III. State Shell’s law.

Answers

Answered by naniharsha948
0

Answer:

1.Given: Light enters from air to kerosene having refractive index of 1.47. The speed of light in air is 3×10

8

m/s

To find the speed of the light in kerosene

Solution:

We know,

Refractive index of the medium=

Speed of light in the medium

Speed of light in air

Hence,

Refractive index of the kerosene=

Speed of light in the kerosene

Speed of light in air

⟹1.47=

Speed of light in the kerosene

3×10

8

⟹Speed of light in the kerosene=

1.47

3×10

8

⟹Speed of light in the kerosene=2.04×10

8

m/s

is the required speed of light in kerosene.

Answer By

Explanation:

2.

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