Question

The region enclosed between the curves y = (sqrt x)*(e^x) and y = e*(sqrt x) is rotated through 2pi
about the x-axis. Find the volume of the solid obtained.​

Answer 1

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✒️Your Question :-

➡️The region enclosed between the curves y = (sqrt x)*(e^x) and y = e*(sqrt x) is rotated through 2pi

about the x-axis. Find the volume of the solid obtained.

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✒️ Answer :-

V=πb∫a([f(x)]2−[g(x)]2)dx. At a point x on the x−axis, a perpendicular cross section of the solid is washer-shape with the inner radius r=g(x) and the outer radius R=f(x).

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➡️ hope this helps you ❗️❗️

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