Math, asked by harshithacharan, 3 months ago

The regression equation of y on x is 4y = 9x + 15
The regression equation of x on y is 25x = 6y +7
Find the mean values of x, y and r.​

Answers

Answered by gg9614176
3

Answer:

the main value of X is 15

the the value of y is is 7

the main value of r is 22

Answered by anvitanvar032
0

Answer:

The correct answer of this question is x  = \frac{118}{46} . y = \frac{438}{46}

Step-by-step explanation:

Given - The regression equation of y on x is 4y = 9x + 15 and the regression equation of x on y is 25x = 6y +7

To Find - Find the mean values of x, y and r.

4y = 9x + 15 and  25x = 6y +7

y = \frac{9}{4} x + \frac{15}{4} and y = \frac{25}{6} x -\frac{7}{6}

\frac{9}{4} x + \frac{15}{4} and y=  \frac{25}{6}x - \frac{7}{6}

\frac{9}{4} < \frac{25}{6}

b_{xy} = \frac{9}{4} . \frac{1}{b_{x} y} = \frac{25}{6}

b_{xy} = \frac{9}{4} . b_{x}y = \frac{6}{25}

r = \sqrt{b_{x} y} × \sqrt{b_{y} x}

= \sqrt{\frac{6}{25} } × \sqrt{\frac{9}{4} }

= \sqrt{90.54}

r = ± 0.7348

r = 0.7348 ...(b_{xy,b_{yx > 0 } })

So, the value of x  = \frac{118}{46} . y = \frac{438}{46}

#SPJ2

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