the regression line 5x+2y=16 and 9x+10y intersect is
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Given : lines 5x+2y=16 and 9x+10y = 48
To Find : Intersection point
Solution:
5x+2y=16 Eq1
9x+10y = 48 Eq2
5 * Eq1
=> 25x + 10y = 80
Subtract Eq2
=> 16x = 32
=> x = 2
Substitute x = 2 in Eq1
5x+2y=16
=> 5(2) + 2y = 16
=> 2y = 6
=> y = 3
Intersection point
x = 2 , y = 3
( 2, 3)
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IdyllicAurora:
Nice :)
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