English, asked by guptarangita061996, 1 month ago

the regulation of a line at full load 0.8 of lagging is 12% yhe regulation of full load 0.8 of leading can be ans plz​

Answers

Answered by ravilaccs
0

Answer:

Regulation of a line at full load is given by4.6

Given:

Voltage regulation is the change in secondary terminal voltage from no load to full load at a specific power factor of load and the change is expressed in percentage.

$E_{2}=$ no-load secondary voltage

$V_{2}=$ full load secondary voltage

To find:

Voltage regulation for the transformer is given by the ratio of change in secondary terminal voltage from no load to full load to no load secondary voltage.

Voltage regulation $=\frac{E_{2}-V_{2}}{E_{2}}$

It can also be expressed as,

Regulation $=\frac{I_{2} R_{02} \cos \phi_{2} \pm I_{2} X_{02} \sin \phi_{2}}{E_{2}}$

Regulation $=\% R \cos \phi \pm \% X \sin \phi$

$+$ sign is used for lagging loads

- ve sign is used for leading loads

Where $\% R=$ ohmic drop

$\% X=$ reactance drop

Calculation:

Ohmic loss $(\% R)=1 \%$

Reactance {drop}(\% X)=5 \%$

Power factor $=\cos \phi=0.8$ lagging

$\therefore \sin \phi=0.6$

Regulation $=\% R \cos \phi \pm \% X \sin \phi$

$$=2(0.8)+5(0.6)=4.6 \%$$

Answered by barmansuraj489
0

Answer:

Line regulation refers to a power supply's capacity to maintain a consistent output voltage despite variations in the input voltage while maintaining a constant output current.

Given:

Voltage regulation is the change in secondary terminal voltage from no load to full load at a specific power factor of load and the change is expressed in percentage.

E2->no-load secondary voltage.

V2-> full load secondary voltage.

To find:

Voltage regulation for the transformer is given by the ratio of change in secondary terminal voltage from no load to full load to no load secondary voltage.

Solution:

Voltage regulation

\frac{E2-V2}{E2}

It can also be expressed as,

Regulation

RcosФ±‰XsinФ

+ve sign is used for lagging loads

- ve sign is used for leading loads

Where ‰R ohmic drop

X reactance drop

Ohmic loss 1

Reactance 5

Regulation

=2(0.8)+5(0.6)\\=4.6

Final answer:

So, the final answer of the question is 4.6‰.

#SPJ3

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