Question

The relation between internal energy U pressure P Volume V of a gas in an adiabatic process is U=a+bPV where a and B are positive constants. What is the value of gamma..... plz say frnds help meee​

Answer 1

Answer:

In an adiabatic process no heat is exchange. i.e. (dQ=0)

dQ=dU+PdV

0=dU+PdV

d(a+bPV)+PdV=0 ... (V=a+bPV..(given))

bPdV+bVdP+PdV=0

(b+1)PdV+bVdP=0

(b+1)(dV/V)+b(dP/P)=0 ... (dividing both by PV)

Integrating we get,

(b+1)logV+b(logP)= constant

logV

(b+1)

+logP

b

= constant

V

(b+1)

×P

b

= constant

Multiply power by

b

1

PV

((b+1)/b)

=constant=PV

γ

γ=

b

b+1

Explanation:

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Answer 2

Answer:

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Explanation:

In an adiabatic process no heat is exchange. i.e. (dQ=0)

dQ=dU+PdV

0=dU+PdV

d(a+bPV)+PdV=0 ... (V=a+bPV..(given))

bPdV+bVdP+PdV=0

(b+1)PdV+bVdP=0

(b+1)(dV/V)+b(dP/P)=0 ... (dividing both by PV)

Integrating we get,

(b+1)logV+b(logP)= constant

logV

(b+1)

+logP

b

= constant

V

(b+1)

×P

b

= constant

Multiply power by

b

1

PV

((b+1)/b)

=constant=PV

γ

γ=

b

b+1