The relation between the displacement x and the time t for a body of mass 2 kg moving under the action of a force is given by x=t^(3)//3 , where x is in metre and t in second ,Calculate the work done by the body in first 2 seconds.
Answers
Answered by
1
Answer:
Hey Mate
hope it may be helpful
Explanation:
Given that,
Mass M=2kg
Displacement = x
Time t=2s
Now, the displacement is
x= t^3/3
On differentiate
dt/dx
=
3
3t
2
dt
v=t
2
dt
Again differentiate
dt
dv
=2tdt
a=2tdt
Now, the force is
F=ma
F=2×2t
F=4t
Now, the work done is
dW=F⋅dx
dW=4t×t
2
dt
dW=4t
3
dt
Work done during t = 0 to 2 sec is found by integration
∫dW=
0
∫
2
4t
3
dt
W=[(2)
4
−0]
W=16J
Hence, the work done is 16 J
Answered by
0
Answer:
Explanation:
the work done will be = 4 kg /mg sq
Similar questions