The relation between the"energy" E and the freqency v of a photon is repressed by the equation E = hv , where h is plank's Writen down s_(t) = u + (a)/(2) (2t-1) , where u is initial of h and its dimensions.
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The dimensions of h are [ M L² T⁻¹ ]
Given :
- E = hv where E is energy, v is frequency and h is plank's constant.
To find :
- Dimensions of h.
Solution :
- We rewrite the equation as, h = E/v
- We can get the dimensions of h using dimensional analysis.
- We know that E = work done
= Force × Displacement
- ∴ [E] = [Force] [Displacement]
= [Mass][Acceleration][Displacement]
= [M] [L T⁻²] [L]
= [ M L² T⁻²]
- Frequency is the reciprocal of time.
- ∴ [v] = [ T⁻¹]
- Hence, [h] = [ M L² T⁻²] / [ T⁻¹ ]
[h] = [ M L² T⁻¹ ]
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