Question

The relation between the gas pressure P and average kinetic energy per unit volume E is(a) $P=\frac{1}{2}E$(b) P = E(c) $P=\frac{3}{2}E$(d) $P=\frac{2}{3}E$

Answer 1

Answer:

C) P = (2/3)E

Explanation:

Pressure= P

Volume = E

E = Average Kinetic energy per unit volume = [(1/2) MV² rms} / V

= (1 / 2) × (M / V) × Vrms²

Therefore,  E = (1 / 2)ρVrms²   (1)

Pressure = P = (1/3) ρVrms²

= ρ∙Vrms² = 3

Hence, from eq (1),

E = (1/2) × 3P = (3/2)P

P = (2/3)E

Thus, the relation between the gas pressure P and average kinetic energy per unit volume E is P = (2/3)E

Answer 2

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The relation between the gas pressure P and average kinetic energy per unit volume E is(a) $P=\frac{1}{2}E$

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