Physics, asked by mehtakavita2474, 1 year ago

the relation between the time t and position x for a particle moving on x-axis is given by t=px2 = qx where p and q are constants .The relation between velocity v and acceleration a is as_______.

Answers

Answered by alinakincsem
5

t=px2+qx

on differentiating wrt t , we have

1=2pxv+qv (1)

on differentiating wrt x , we have

0=2pv+2px.dv/dx +q.dv/dx

0=2pv+2px.(a/v) +q.(a/v)

0=2pv2+2pxa +qa (2)

from (1) and (2)


Thus:

2pv3+a=0

Answered by chaitanyasmahajan
3

t=px2+qx


on differentiating wrt t , we have


1=2pxv+qv (1)


on differentiating wrt x , we have


0=2pv+2px.dv/dx +q.dv/dx


0=2pv+2px.(a/v) +q.(a/v)


0=2pv2+2pxa +qa (2)


from (1) and (2)



Thus:


2pv3+a=0

now, we can conclude that 'a' is directly proportional to 'v³'.

Similar questions