the relation between the time t and position x for a particle moving on x-axis is given by t=px2 = qx where p and q are constants .The relation between velocity v and acceleration a is as_______.
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Answered by
5
t=px2+qx
on differentiating wrt t , we have
1=2pxv+qv (1)
on differentiating wrt x , we have
0=2pv+2px.dv/dx +q.dv/dx
0=2pv+2px.(a/v) +q.(a/v)
0=2pv2+2pxa +qa (2)
from (1) and (2)
Thus:
2pv3+a=0
Answered by
3
t=px2+qx
on differentiating wrt t , we have
1=2pxv+qv (1)
on differentiating wrt x , we have
0=2pv+2px.dv/dx +q.dv/dx
0=2pv+2px.(a/v) +q.(a/v)
0=2pv2+2pxa +qa (2)
from (1) and (2)
Thus:
2pv3+a=0
now, we can conclude that 'a' is directly proportional to 'v³'.
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