Question

The relation between time t and distance x is T = Alfa x square + beta x where Alpha hand beta are constants . The retardation is
1) 2×alfa×v**3
2) 2×beta×v**2
3)2×alfa×beta×v**2
4)2×beta×v**3

Answer 1

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t = ax² + bx

differentiate with respect to x

dt/dx = 2ax + b

dx/dt = V = 1/(2ax + b)

again, differntiate with respect to t

d²x/dt² = -2a/(2ax + b)²

put V = 1/(2ax + b)

d²x/dt² = acceleration = -2aV²



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Answer 2

CONSIDER a = alpha

b=beta.........

1 option is correct....

Refer the attachment...

hope it help ...