Question

The relation between time t and distance x is t = ax + bx
where a and b are constants. The acceleration is
(a) -2av^3 (6) 2av^2
(c)-2av^2 (d) 2bv^3


plese tell correct answer​

Answer 1

Answer:

(a) -2av³

Explanation:

Given t = ax² + bx ---(1)

Differentiating eq(1) with respect to t:

1 = 2axx' + bx' ----(2). 2ax + b = 1/x' ---(3)

Differentiating eq(2) with respect to t:

0 = 2a(x')² + 2axx" + bx"

x"(2ax + b) = - 2a(x')²

x" = - 2a(x')²/(2ax + b)

x" = - 2a(x')²x'. {from (3)}

now put x' = v, x" = acceleration

acceleration = -2av³

Thank you.