Question

the relation between time t and distance x is t=αx^2 +βx where α and β are constants the retardation is
​

Answer 1

Answer:

t=ax

2

+bx

Differentiate w.r.t time

1=2ax

dt

dx

+b

dt

dx

dt

dx

=

2ax+b

1

V=

2ax+b

1

...(1)

a=

dt

dV

=

(2ax+b)

2

−(2a

dt

dx

)

a=

(2ax+b)

2

−2av

....(2)

Substiting

2ax+b

1

=V in (2)

we will get, a=−2av

3

Answer 2

Answer:

the relation between time t and distance x is t=αx^2 +βx where α and β are constants the retardation is

Explanation:

sorry point le raha tha