The relation t = VX + 3 describes the position of a
particle where x is in meters and t is in seconds.
(1) 2 m/s2
(3) 5 m/s
The acceleration of particle is :-
(2) 4 m/s2
(4) zero
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Answer:
Correct option is
D
zero
t=
x+3
Velocity=0
t=x
1/2
+3
t−3=x
1/2
(t−3)
2
=x
dt
dx
=2(t−3)
For v=0
o=2t−6
t=3s
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