The relation to calculate ph of a weak base in log
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There is weak base , so it's a strong acid. Therefore , it's pH will decrease and pOH will increase.
For ex.
I have 0.05M CH3COOH is strong acid and weak base. So
by taking value of Ka from table = 1.74 × 10-5
and solving it,
I get alfa= 1.86 × 10-2
Further from that I get value of H+ = 9.3 × 10-4
From that pH is easily find
pH = - log [H+]
= -log [9.3× 10-4]
= - [ -4 + 0.9685]
pH = 3.03
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