The relative atomic mass of an element A is
16.2. There are two isotopes 16 A and 18A of the
element. Calculate the percentage of these two
isotopes present in the element.
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Answer:
Let the percentage of isotope X-16 = x
The percentage of isotope X-18 = 100-x
Relative atomic mass = 16.2
Formula: Relative atomic mass =
Putting the value of parameter in above formula
16.2 = [16x + 18(100-x)] /100
The value of x is 90
Therefore percentage of isotope of mass no. 16 is 90%, while for isotope-18 is 10%
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