Question

The relative density of a mixture of nitrogen and oxygen is 14.4 (H = 1) and the relative densities of nitrogen and oxygen are 14.0 and 16.0 (H = 1) respectively. Calculate the composition of the mixture (i) by volume and (ii) by mass.​

Just tell me what does "H=1" mean in this question!

Answer 1

Answer:

$(i) \: Let \: 1 \: of \: the \: mixture \: contain \: x \: ml \: of \: N2 \: and \: (1 - x) mL of N2 \: = 140 \times x \: = 14xg \: (Mass = d \times v) \: \\ Mass of (1 - x) mL of \: O2 \: = 16.0 \times (1 - x) \: = (16.0 - 16x)g \\ Total mass of mixture = 14x + 16.0 - 16x = 14.4 \times 1 = 14.4 \\ (ii) Let 1 g of the mixture contain x g of  and (1- x) g of N2 \: oxygen. </p><p>Volume of x g of \\ \: N2 \: = \frac{x}{14.0} \\ Volume of (1-x) g of \: O2 = \: \frac{(1 - x)}{16.0} \\ Total volume of the mixture  = \: \frac{1}{14.0} + \: \frac{(1 - x)}{16.0} \\ So,  \frac{1}{14.0} + \frac{(1 \times x)}{16.0} = \frac{1}{14.4} \\ or    x=0.7778 \: example \: 77.78percent \: by \: mass \\ oxygen \\ = (1 - x) = (1 - 0.7778) = 0.2222 \: or \: 22.22percent \: by \: mass$

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