Question

the relative density of silver is 10.8. if the density of water be 1.0 ×10³ kg m-³. calculate the density of silver in SI unit.​

Answer 1

Answer:

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Question:-

the relative density of silver is 10.8. if the density of water be 1.0 ×10³ kg m-³. calculate the density of silver in SI unit.

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Solution:-

Given ,

the relative density of silver = 10.8.

the density of water = 1.0 ×10³ kg m-³.

To Find :-

Density Of Silver

We Know That ,

Relative density of a substance,

$\sf{ \rm \red{ = \: \frac{density \: of \: substance}{density \: of \: water} }}$

Now , Putting the value of relative density of silver and density of water in the above formula :

$\sf10.8 = \frac{ \sf{ \rm {density \: of \: silver}}}{1.0 \times {10}^{3} }$

So , density of silver = 10.8×1.0×10³ kg m-³

= 10.8 × 10³ kg m-³

Thus , The density of silver in SI Units is 10.8 × 10³ kg m-³.

This can also be written as 10800 kg m-³.

Answer 2

Answer:

the relative density of silver = 10.8.

the density of water = 1.0 ×10³ kg m-³.

To Find :-

Density Of Silver

We Know That ,

Relative density of a substance,

\sf{ \rm \red{ = \: \frac{density \: of \: substance}{density \: of \: water} }}=densityofwaterdensityofsubstance

Now , Putting the value of relative density of silver and density of water in the above formula :

\sf10.8 = \frac{ \sf{ \rm {density \: of \: silver}}}{1.0 \times {10}^{3} }10.8=1.0×103densityofsilver

So , density of silver = 10.8×1.0×10³ kg m-³

= 10.8 × 10³ kg m-³

Thus , The density of silver in SI Units is 10.8 × 10³ kg m-³.

This can also be written as 10800 kg m-³.