Question

The relative density of silver is 10.8. if the density of water be 1.0 × 10³ kgm^-3 , calculate the density of silver in SI units .​

Answer 1

$\huge\star\sf\underline\pink{Solution:-}$

$\orange{\boxed{\sf{Relative\: Density\:of\:a\: substance = \dfrac{Density\:of\:the\: substance}{Density\:of\:water} }}}$

$\sf\red{Here,} \\ \\ \sf{Relative\: density\:of\: silver = 10.8} \\ \\ \sf{Density\:of\: silver =?} \: \: \: \sf\purple{(To\:be\: calculated)} \\ \\ \sf{and,} \\ \\ \sf{Density\:of\:water = 1.0 \times 10^3\: kg \:m^-3 } \\ \\ \sf\red{Now,} \\ \\ \sf{Putting\: these\: Values :-}$

${\sf{10.8 = \dfrac{Density\:of\: silver}{1.0 \times 10^3} }} \\ \\ \sf{Now,} \\ \\ \sf{ Density\:of\: silver = 10.8 \times 1.0 \times 10^3 \:kg \: m^-3 } \\ \\ \implies{\boxed{\sf{10.8 \times 10^3 kg\:m^-3}}}$

$\sf{Thus,} \\ \\ \sf\blue{The\: density\:of\:silver\:in\:SI\:units\:is\:10.8 \times 10^3 \: kg\: m^-3.}$

$\sf\underline\pink{Thanks}$

Answer 2

Answer:

⋆

Solution:−

\begin{lgathered}\\ \\\end{lgathered}

\orange{\boxed{\sf{Relative\: Density\:of\:a\: substance = \dfrac{Density\:of\:the\: substance}{Density\:of\:water} }}}

RelativeDensityofasubstance=

Densityofwater

Densityofthesubstance

\begin{lgathered}\\\end{lgathered}

\begin{lgathered}\sf\red{Here,} \\ \\ \sf{Relative\: density\:of\: silver = 10.8} \\ \\ \sf{Density\:of\: silver =?} \: \: \: \sf\purple{(To\:be\: calculated)} \\ \\ \sf{and,} \\ \\ \sf{Density\:of\:water = 1.0 \times 10^3\: kg \:m^-3 } \\ \\ \sf\red{Now,} \\ \\ \sf{Putting\: these\: Values :-} \\ \\\end{lgathered}

Here,

Relativedensityofsilver=10.8

Densityofsilver=?(Tobecalculated)

and,

Densityofwater=1.0×10

3

kgm

−

3

Now,

PuttingtheseValues:−

\begin{lgathered}{\sf{10.8 = \dfrac{Density\:of\: silver}{1.0 \times 10^3} }} \\ \\ \sf{Now,} \\ \\ \sf{ Density\:of\: silver = 10.8 \times 1.0 \times 10^3 \:kg \: m^-3 } \\ \\ \implies{\boxed{\sf{10.8 \times 10^3 kg\:m^-3}}}\end{lgathered}

10.8=

1.0×10

3

Densityofsilver

Now,

Densityofsilver=10.8×1.0×10

3

kgm

−

3

⟹

10.8×10

3

kgm

−

3

\begin{lgathered}\\\end{lgathered}

\begin{lgathered}\sf{Thus,} \\ \\ \sf\blue{The\: density\:of\:silver\:in\:SI\:units\:is\:10.8 \times 10^3 \: kg\: m^-3.} \\ \\\end{lgathered}

Thus,

ThedensityofsilverinSIunitsis10.8×10

3

kgm

−

3.

\sf\underline\pink{Thanks}

Thanks