Question

The relative lowering of v. p. of the solution having total number of moles equal to 2.5 is 0.06. How many number of moles of solute are present in the solution?​

Answer 1

Answer:

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Answer 2

Answer:

0.15  moles of solute are present in the solution having relative lowering of

v. p. of the solution having total number of moles equal to 2.5 is 0.06

Explanation:

The relative lowering of v. p. of the solution

                      $\frac{\delta_P}{P} =x_{2}$

     Where $x_{2}$ is mole fraction of solute in the solution

$\frac{\delta_P}{P} =\frac{n_{2} }{n_{total} } \\ \\ 0.06=\frac{n_{2} }{2.5} }\\ \\ n_{2} =(0.06)(2.5)\\ \\ n_{2} =0.15$