Question

the relative rates of diffusion of Cl2 and CO2 gases​

Answer 1

Graham's law states that the rate of effusion (or of diffusion ) of a gas is inversely proportional to the square root of it's molecular weight. The rate of diffusion is themeasure of rate at which two gases mix, and the rate of effusion is the measure of rate at which a gas escapes through a pinhole into a vacuum.

Answer 2

The relative rate of effusion of $Cl_2$ and $CO_2$ is 0.79

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

So,

$\frac{\text{Rate}_{Cl_2}}{\text{Rate}_{CO_2}}=\sqrt{\frac{M_{CO_2}}{M_{Cl_2}}}$

We are given:

Molar mass of chlorine gas = 71 g/mol

Molar mass of carbon dioxide gas = 44 g/mol

Putting values in above equation, we get:

$\frac{\text{Rate}_{Cl_2}}{\text{Rate}_{CO_2}}=\sqrt{\frac{44}{71}}\\\\\frac{\text{Rate}_{Cl_2}}{\text{Rate}_{CO_2}}=0.79$

Learn more about Graham's law:

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