Question

The relative size of isoelectronic species o2-,F-,Ne and Na+ is determined by (A) nuclear charge (B) electron
-electron repulsion in outer shell (principal) quantum number of valence shell (D) nature of charge on the species​

Answer 1

Answer:

The relative size of isoelectric species is determined by- (A) nuclear charge.

Explanation:

The size of isoelectronic species depends on nuclear charge. As the nuclear attractions increases the electrons are strongly bound to nucleas.

In F- ion, no. of electrons are more than that of protons. So, its size is more than that of a F atom, as the nuclear charge per electron will be less.

Na+ has one electron less than that of Na. So, nuclear charge per electron increases, and they are strongly bound to nucleus, decreasing the size.

Answer 2

Answer:

nuclear charge

Explanation:

the answer is nuclear charge because, as the nuclear attractions increase(no of protons are increased) so that, the attraction acting on electron increases so that, the electrons are more strongly attached to the nucleus (i mean they have higher Ionisation potential) . if the attractions are more, the radius size will be small.