Question

the relativistic mass of a proton moving with a speed of 2.4

Answer 1

The relativistic mass of a body of rest mass $m_0$ is

$m=\frac{m_0}{\sqrt{1-\frac{v^2}{c^2}}}$, where $v$ is the speed of the body and $c$ is the speed of light.

For a proton, $m_0=1.61*10^{-27}\; kg, c=3*10^8\;m/s,v=2.4*10^8\;m/s$.

Substituting numerical values,

[tex] m=\frac{1.61*10^{-27}}{\sqrt{1-\frac{(2.4*10^8)^2}{(3*10^8)^2}}} \\

m=2.683*10^{-27}\;kg [/tex]