the remainder contains no term in x^2, when x^5+kx^2 is divided by (x-1)(x-2)(x-3), then the value of k is? plzz reply faster. it's very urgent
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p(x)=x5+kx2
p(1)=1+k
0=k+1
k=-1
p(2)=32+4k
0=32+4k
k=-32/4
k=-8
p(3)=729+9k
0=729+9k
k=-729/9
k=-81
I hope it helps to you
p(1)=1+k
0=k+1
k=-1
p(2)=32+4k
0=32+4k
k=-32/4
k=-8
p(3)=729+9k
0=729+9k
k=-729/9
k=-81
I hope it helps to you
laya2004:
option 81 is not there
the options are 90,80,-80,-90
can u pls explain once more
i'm sorry for the inconvenience.
your ans is correct
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