Question

The remainder obtained on dividing 123 by 2 is​

Answer 1

Answer:

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Step-by-step explanation:

Given that: 1!+2!+3!+4!+...........+11!

=(1!+2!+3!)+(4!+5!+......+11!)

=(1+2+6)+(4!+5!+........+11!)

=9+(4!+5!+.......+11!)

4!,5!,........11! are divisible by 12

So when you will divide given expression by 12 the remainder will be 9

Answer 2

Answer for this ques is

one (1)