Question

The remainder obtained when 23(23)(23)+31(31)(31)is divided by
54​

Answer 1

23 x23x23 + 31x31x31 = (23)^3 + (31)^3
Now we know the identity => a^3 + b^3 = (a+b)(a^2+b^2-ab)
So this is devisible by a+b
=> 23^3 + 31^3 is devisible by (23+31) i.e 54
So remainder is 0

Answer 2

answer is 777

hope it helps u :)