The remainder obtained when 23^3 + 31^3 is divided by 54.
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Remainder is 0
B/z 23^3 +31^3is of the form a^n + b^n
and any no of such form is divisible by a+b when n is odd
B/z 23^3 +31^3is of the form a^n + b^n
and any no of such form is divisible by a+b when n is odd
Hitech:
canu solve it with the help of hcf and lcm
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