Question

the remainder obtained when F(x)=x^3+6x^2+2x-4 is divided by (1-2x)​

Answer 1

Answer:

$\bf{1-2x=0}$

$\bf{x=\dfrac{1}{2}}$

Now put this values in this function of the equation ,

$f( \frac{1}{2} ) = ( { \frac{1}{2} })^{3} + 6( { \frac{1}{2} })^{2} + 2 \frac{1}{2} - 4$

$f( \frac{1}{2} ) = \frac{1}{8} + \frac{3}{2} + 1 - 4$

$f( \frac{1}{2} ) = \frac{1 + 12}{8} - 3$

$f( \frac{1}{2} ) = \frac{13}{8} - 3$

$f( \frac{1}{2} ) = \frac{13 - 24}{8}$

$f( \frac{1}{2} ) = \frac{ - 11}{8} \: is \: the \: remainder \: of \: this \: equation$