Question

The remainder obtained when t^6+3t^2+10 is divided by t^3+1

Answer 1

Answer:

t^3+1=0

=> t = -1

Putting value of the in equation we get value : (-1)^6 + 3×(-1)^2 +10

= 1 + 3 + 10 = 13

So 13 is remainder.

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