Question

The remainder obtained when t6 + 3t2 + 10 is divided by t3 + 1 is

Answer 1

Answer:

when we find the zero of the polynomial

p(x)=t^6+3t^2+10

g(x)=t^3+1

t^3+1=0

t^3=-1

t=cube root of -1

=-1

now,

p(-1)=(-1)^6+3(-1)^2+10

=1+3+10

=14

is right

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Answer 2

Answer:

We divide the polynomial t

6

+3t

2

+10 by t

3

+1 as shown in the above image and we observe that the quotient is t

3

−1 and the remainder is 3t

2

+11.The remainder obtained when t

6

+3t

2

+10 is divided by t

3

+1 is: