Math, asked by satwik222005, 6 months ago

the remainder of x^4+4x^3-5x^2+6x+7 when divided by (x+2).
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Answered by Anonymous

1

Answer:

x^4+4x^3-5x^2+6x+7/x+2

Quotient = x^3+2x^2-9x+24

Remainder = -41

Answered by shivangisingh50

2

Answer:

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Step-by-step explanation:

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