The remainder of x⁴ + x³ – x² + 2x + 3 when divided by x – 3 is
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Answer:
x-3 = 0
x=3
f(x) = x⁴+ x³- x²+ 2x+ 3
= (3)⁴+ (3)³-(3)²+2(3)+3
= 81+27-9+6+3
= 108+9-9
=108
Answer is 108
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