Question

the remainder when 1000²⁰¹⁸ is divided by 2018​

Answer 1

Answer:

Step-b2018=(2020−2)=(101⋅20−2)

For some integers k and m;

20182018=k⋅20+(−2)2018

=k⋅20+41009

This obviously divides by 4; what's the remainder after dividing by 5?

20182018=k⋅20+(5−1)1009

=k⋅20+5⋅m+(−1)1009

=k⋅20+5⋅m−1y-step explanation: