the remainder when 2^2017 is divided by 5 will be:
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if we know what is unit digit of 2^2017 then we can say that what remainder .
divide 2017 by 4 remains = 1
hence , unit digit of 2^2017 is 2 ,
now two last no possible 02 , 12 , 22 , 32, 42 , ....92
we see always remain to all of these 2
hence, remainder =2
divide 2017 by 4 remains = 1
hence , unit digit of 2^2017 is 2 ,
now two last no possible 02 , 12 , 22 , 32, 42 , ....92
we see always remain to all of these 2
hence, remainder =2
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