Question

the remainder when (20)¹⁶⁵¹+(15)¹⁶⁵¹is divisible by 35 is
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Answer 1

Answer:

The final answer is 0.

Step-by-step explanation:

Given,

$20^1^6^5^1$ + $15^1^6^5^1$, We need to find the remainder of the equation given when it is divided by 35. First and foremost, There is a theorem in maths that states that if a number a+b is divisible by c, then $a^m +a^n$ is divisible by c if and only if m = n. Here we have two numbers 20+15.

From the first rule,

We find out that 20 + 15 = 35 is divisible by 35. Since the powers of both 20 and 15 are same, 1651, Hence $15^1^6^5^1$+$20^1^6^5^1$ is divisible by 35. Hence the remainder will be zero.

Divisibility

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