Question

the remainder when 2x cube +5x square-6x+2 is divided by (x+2) is​

Answer 1

Answer:

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

(((2 • (x3)) - 5x2) + 6x) - 2 = 0

STEP

2

:

Equation at the end of step

2

:

((2x3 - 5x2) + 6x) - 2 = 0

STEP

3

:Checking for a perfect cube

3.1 2x3-5x2+6x-2 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 2x3-5x2+6x-2

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 6x-2

Group 2: 2x3-5x2

Pull out from each group separately :

Group 1: (3x-1) • (2)

Group 2: (2x-5) • (x2)

Answer 2

Answer:

The remainder is $18$.

Step-by-step explanation:

The remainder is determined using the method of zeros of polynomial.

It is given that the polynomial $P(x)=2x^{3} +5x^{2} -6x+2$

Quotient is $x+2$.

Equating quotient to zero,

$x+2=0$

$x=-2$

Putting this value of zero in polynomial.

$P(x)=2x^{3} +5x^{2} -6x+2$

$P(-2)=2(-2)^{3} +5(-2)^{2} -6(-2)+2$

$P(-2)=2(-8)+5(4)+12+2$

$P(-2)=-16+20+12+2$

$P(-2)=18$

Hence, the remainder is $18$.

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