Question

The remainder when 2xcube+3xsquare+4x+5 is divided by (x-2)
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Answer 1

Answer:

Remainder = 41

Step-by-step explanation:

P(x) = 2x³ + 3x² + 4x + 5

Divisor = x - 2

⇒ x - 2 = 0

⇒ x = 2

Using remainder theorem

⇒ P(x) = 2(2)³ + 3(2)² + 4(2) + 5

= 2(8) + 3(4) + 8 + 5

= 16 + 12 + 8 + 5

= 41

∴ Remainder = 41