Question

The remainder when 33! Is divided by 2^19 is _______​

Answer 1

(2^5)^19 = 32^19

N 32^19 wen divided by 33 leaves a remainder (-1)^19 = -1

Thus 16*-1=-16

Hence the remainder is 33-16 I.e 17

Answer 2

Answer:

1.6

Step-by-step explanation:

The round up answer is 1.6 but if you want a longer answer it will be 1.6562114