Question

The remainder when 3x^3 – 5x^2 + 4x – 7 is divided by (x – 3) is

Answer 1

Step-by-step explanation:

3x^3 – 5x^2 + 4x – 7

put. x=3

3(3)^3-5(3)^2+4(3)-7

81-45+12-7

93-52

41

Answer 2

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Given f(x)=x

3

−5x

2

+7 and divisor is x+2.

We put x+2=0

∴x=−2

According to remainder theorem,

If f(x) is divided by x−a, the remainder will be f(a).

Here, a=−2.

∴f(−2)=(−2)

3

−5(−2)

2

+7 =−21