Math, asked by AyushmanDas617, 10 months ago

The remainder when 4^ 0+4^1+...4^40 is divided by 17 is

Answers

Answered by Sarfraaz06
3

Answer:

(4^0 + 4^1 + 4^2 + ... + 4^40) / 17

= 1611901092819505566274901/17

= 94817711342323856839700 1/17

Remainder is 1.

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