The remainder when 4^101 is divided by 101 is
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Step-by-step explanation:
Given The remainder when 4^101 is divided by 101 is
- We have Fermat’s little theorem states that for any prime n and any integer a such that n^a – n is an integer multiple of a
- So n is a prime number.
- So n^(a – 1) = 1 (mod a)
- Let n = 4 and a = 101 we get
- So 4^(101 – 1) = 1 (mod 101)
- So 4^100 = 1 (mod 101)
- Multiply both sides by 4 we get
- So 4 x 4^100 = 4 (mod 101)
- So a^m x a^n = a^m + n using this we get
- 4^101 = 4 (mod 101)
- Therefore 4^101 will have a remainder 4 when divided by 101.
Reference link will be
https://brainly.in/question/5477715
https://brainly.in/question/16107102
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