the remainder when 4a³ - 12a² + 14a - 3 is divided by 2a - 1
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Answer:
p(x) = 2x - 1
q(x) = 4a^3 - 12a^2 + 14a -3
2x - 1/ 4a^3 -12a^2 + 14a -3
2x - 1
x = 1/2(In rough column)
= 4(1/2)^3 - 12(1/2)^2 + 14(1/2) - 3
= 4 × 1/8 - 12 × 1/4 + 7 - 3
= 1/2 - 3 + 7 - 3
= 1/2 + 1
= 3/2
Step-by-step explanation:
Therefore 3/2 is the remainder
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