Question

The remainder when
p(x) = 3x^3 + 2x - 6 will be
divided by (x - 1)

Answer 1

Answer:

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Answer 2

Answer:

$(x - 1) = \\ x = 1 \\ p(x) = 3 {x}^{3 } + 2x - 6 \\ 3( {1}^{3} ) + 2(1) - 6 \\ 3(1) + 2 - 6 \\ 3 + 2 - 6 \\ = - 1$

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