The remainder when p(x) is divided by (b-ax) ?
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By Remainder theorem :
If p(x) is divided by ( ax - b ) then the remainder
is p ( b/a ) .
it is easy to find the zero of p( x ) . which is
given below ,
ax - b = 0
ax = b
x = - b/a
i.e remainder is p( -b/a )
Hope it helps you!!!!!!
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