Question

The remainder when p(x) is divided by (x-2) where p(x) is 2x²-x-6​

Answer 1

Step-by-step explanation:

(2x^2-x-6) ÷ (x-2)

x-2=0

x=2

p(x) = 2x^2-x-6

p(2) = 2(6)^2-(6)-6

2(36)-6-6

72

Remainder= 72

Answer 2

x-2=0

X=2

so when we put X=2 in the equation p(X),then

8-2-6=-8+8

=0 so 0 is the remainder and x-2 is the factor of this equation