The remainder when the square of any prime number greater than 3 is divided by 6, is
(a) 1
(b) 3
(c) 2
(d) 4
Answers
Answered by
8
Option (a) is correct : 1
(6k ± 1)² = (6k)² + 1² ± 2 × 6k
= 36k² ± 12k + 1
= 6k ( 6k ± 2) +1
When 6k (6k ± 2) +1 is divided by 6 , we get k(6k ± 2) and Remainder is 1.
Hence, the remainder is 1
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Answered by
5
the correct answer is (a) = 1
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