Question

The remainder, when x'+3x²+3x+1 is divided by x is
​

Answer 1

Answer:

ANSWER

Given, πx+y=9

a) Put x=0, we have

π(0)+y=9

⇒y=9

b) Put y=0, we have

πx+0=9

⇒πx=9

⇒x=

π

9

c) Put x=1, we have

πx+y=9

⇒π(1)+y=9

⇒y=9−π

d) Put x=2, we have

πx+y=9

⇒π(2)+y=9

⇒y=9−2π

Hence, the four solutions of the given equations are: (0,9),(

π

9

,0),(1,9−π),(2,9−2π).

Answer 2

Answer:8

mate .

putting x=1

so,we have polynomial

$x+ 3x^{2}+3x+1$

$1+3×1^{2}+3×1+1$

$4+4$

$8$

remainder=8