Question

the remainder when x cube + 3 X square + 3 X + 1 is divided / X by long division​

Answer 1

Answer:

Answer:

Remainder = -9.84

Step-by-step explanation:

We use the Remainder theorem which states that if a polynomial p(x) is divided with a linear polynomial x - a then the remainder is given by p(a).

Here p(x) = x³ + 3x² + 3x + 1

and linear polynomial = x+\pix+π

now according to remainder theorem,

remainder=p(-\pi)remainder=p(−π)

=(-\pi)^3+3(-\pi)^2+3(-\pi)+1=(−π)

3

+3(−π)

2

+3(−π)+1

=-\pi^3+3\pi^2-3\pi+1=−π

3

+3π

2

−3π+1

we further solve it by putting value of \piπ .i.e, \pi=\frac{22}{7}π=

7

22

remainder=-(\frac{22}{7})^3+3(\frac{22}{7})^2-3(\frac{22}{7})+1remainder=−(

7

22

)

3

+3(

7

22

)

2

−3(

7

22

)+1

remainder=-9.84remainder=−9.84

Therefore, Remainder = -9.84